11th seed Jannik Sinner takes on the experienced Stan Wawrinka in the round of 16 of the 2023 Indian Wells on Tuesday.
The Italian youngster has defeated a couple of French veterans to get to the round of 16. In the round of 64, Sinner defeated Richard Gasquet 6-3, 7-6 (7-2). Sinner had an impressive win percentage of 89 on the first serve and converted 2 out of 4 break points. He also smashed 9 aces in the encounter.
In the round of 32, Sinner had to dig deep to get past Adrian Mannarino in straight sets 7-6 (9-7), 6-4. Sinner was once again very good with his serves. He sent across 6 aces and had a win percentage of 82 on the first serve which increased to 92 on the second serve. Mannarino failed to break his serve during the entire match.
The 37-year-old has battled hard to win three matches so far in the competition. He defeated Aleksandar Vukic in the round of 128 in three sets 6-4, 1-6, 6-1. In the round of 64, Wawrinka produced another gritty effort to get past Miomir Kecmanovic 7-6 (10-8), 6-4. The Swiss veteran had a win percentage of 88 in this match.
Wawrinka went on to beat 7th seed Holger Rune 6-2, 6-7 (5-7), 7-5 in the round of 32. The 3-time Grand Slam champion had a staggering win percentage of 95 on the first serve and he converted 5 out of 8 break points. In the three matches, Wawrinka has recorded 35 aces in total.
Head-to-Head and Prediction
The head-to-head is currently at 2-2. Sinner comprehensively defeated Wawrinka in their most recent encounter, which was in the 2023 ATP Rotterdam Open, in straight sets 6-1, 6-3.
Prediction: Jannik Sinner to win in three sets.
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